Day of the Programmer

Marie invented a Time Machine and wants to test it by time-traveling to visit Russia on the Day of the Day of the Programmer (the 256th day of the year) during a year in the inclusive range from 1700 to 2700.

From 1700 to 2700, Russia’s official calendar was the Julian calendar; since 1919 they used the Gregorian calendar system. The transition from the Julian to Gregorian calendar system occurred in 1918, when the next day after January 31th was February 14 th . This means that in 1918, February 14th was the 32th day of the year in Russia.

In both calendar systems, February is the only month with a variable amount of days; it has 29 days during a leap year, and 28 days during all other years. In the Julian calendar, leap years are divisible by 4 ; in the Gregorian calendar, leap years are either of the following:

Divisible by 400.
Divisible by 4 and not divisible by 100.
Given a year, y, find the date of the 256th day of that year according to the official Russian calendar during that year. Then print it in the format dd.mm.yyyy, where dd is the two-digit day, mm is the two-digit month, and yyyy is y.

Input Format

A single integer denoting year y.

Constraints

Output Format

Print the full date of Day of the Programmer during year y in the format dd.mm.yyyy, where dd is the two-digit day, mm is the two-digit month, and yyyy is y.

Solution

process.stdin.resume();
process.stdin.setEncoding('ascii');

var input_stdin = "";
var input_stdin_array = "";
var input_currentline = 0;

process.stdin.on('data', function (data) {
    input_stdin += data;
});

process.stdin.on('end', function () {
    input_stdin_array = input_stdin.split("\n");
    main();    
});

function readLine() {
    return input_stdin_array[input_currentline++];
}

/////////////// ignore above this line ////////////////////

function solve(year){
    if (year == 1918)
        return '26.09.1918'
    else if (((year  1918) && (year%400 == 0 || ((year%4 == 0) && (year%100 != 0)))))
        return '12.09.' + year
    else
        return '13.09.' + year
}

function main() {
    var year = parseInt(readLine());
    var result = solve(year);
    process.stdout.write(""+result+"\n");

}

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